75 lines
1.5 KiB
Plaintext
75 lines
1.5 KiB
Plaintext
/*
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Quick and dirty program to make intel-hex from a binary.
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Written by R.E.Wolff@BitWizard.nl
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This file is in the public domain
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Typing started:
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Mon Jun 16 00:24:15 MET DST 1997
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programming stopped:
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Mon Jun 16 00:31:27 MET DST 1997
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debugging finished (2 bugs found):
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Mon Jun 16 00:32:52 MET DST 1997
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---------------------------------------------------------
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Doc written in timeout. Everything else in this file was done while
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the timer was running.
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I promised "Mark Kopecki" that writing the bin-to-intel-hex
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converter would cost less than 15 minutes, and that it would be more
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trouble to find a converter on the net than to write the converter
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myself. I ended up spending over half an hour searching for
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spec/converter/docs because of unreachable hosts on the internet. I
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got a file with docs, after that it was 8 minutes.....
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---------------------------------------------------------
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*/
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#include <stdio.h>
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#include <unistd.h>
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/* Intel Hex format:
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ll aaaa tt dd....dd cc
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ll = length
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aaaa = address
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tt = type
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dd....dd = data
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cc = checksum.
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*/
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int main (int argc, char **argv)
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{
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unsigned char buf[32];
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int addr = 0;
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int n,i;
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while ((n = read (0, buf+4, 16)) > 0) {
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buf[0] = n;
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buf[1] = addr >> 8;
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buf[2] = addr & 0xff;
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buf[3] = 0x00;
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buf[4+n] = 0x00;
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for (i=0;i<4+n;i++)
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buf[4+n] -= buf[i];
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printf (":");
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for (i=0;i<= 4+n;i++)
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printf ("%02x", buf[i]);
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printf ("\n");
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addr += n;
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}
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printf (":0000000001ff\n");
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exit (0);
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}
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